Question

Four rods that obey Hooke's law are each put under tension.

a. A rod 50.0 cm long with cross-sectional area 1.00 mm2 and with a 200 N force applied on each end.
b. A rod 25.0 cm long with cross-sectional area 1.00 mm2 and with a 200 N force applied on each end.
c. A rod 20.0 cm long with cross-sectional area 2.00 mm2 and with a 100 N force applied on each end. Order the rods according to the tensile stress on each rod, from smallest to largest.

Order the rods according to the tensile stress on each rod, from smallest to largest.

1. c < b < a
2. a=b 3. a< b < c
4. c

Answer 1

c < a<=b

Step-by-step explanation:

Tensile stress = (force) /Area

for A:

Tensile stress = 200/1 =200N/mm²

For B:

Tensile stress = 200/1 =200N/mm2

For C:

Tensile stress = 100/2 =50N/mm²

Ranking from smallest to largest we have;

C<A<=B which is option 4