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The point (-6, 4) lies on a straight line that has a gradient of -2. What is the

equation of this line?

User Jshock
by
8.6k points

1 Answer

4 votes

Given:

Point on straight line = (-6,4)

Gradient = -2

To find:

The equation of the line.

Solution:

Point-slope form: If a line passes through the point
(x_1,y_1) with slope m, then the equation of the line is


y-y_1=m(x-x_1)

The line passes through the point (-6,4) with slope -2. So, the equation of the line is:


y-4=-2(x-(-6))


y-4=-2(x+6)


y-4=-2x-12

Adding 4 on both sides, we get


y-4+4=-2x-12+4


y=-2x-8

Therefore, the equation of the line is
y=-2x-8.

User Shambhav
by
8.1k points

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