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Calculate the number of moles of NaOH contained in 250. mL of a 0.05M solution?

User Walker
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Answer:

0.0125 moles of NaOH are present

Step-by-step explanation:

Molarity, M, is an unit of concentration widely used in chemistry. Is defined as the ratio between moles of solute (In this case, NaOH) and liters of solution.

250.0mL are = 0.250L of solution. As the molarity of the solution is 0.05M = 0.05moles / 1L, the moles present are:

0.250L * (0.05moles / 1L) =

0.0125 moles of NaOH are present

User Zhihuifan
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