Answer:
Perimeter of trapezoid = 25.66 cm
Explanation:
Trapezoid ABCD contains two triangles ΔABF, ΔCDE and a square with side length 4 cm.
By applying Pythagoras theorem in ΔABF,
AB² = BF² + AF²
AB² = 4² + 3²
AB =
![√(16+9)](https://img.qammunity.org/2022/formulas/mathematics/high-school/zbf25251nvtdcmekxakji2p0f9qmzeffan.png)
AB = 5 cm
Similarly, By applying Pythagoras theorem in ΔCDE,
CD² = DE² + CE²
CD² = 4² + 4²
CD =
![√(32)](https://img.qammunity.org/2022/formulas/mathematics/high-school/3amvujuclnlc2xx1w4efkgfzo070y5rb.png)
CD =5.66 cm
Perimeter of the given trapezoid = AB + BC + CD + AD
= 5 + 4 + 5.66 + (3 + 4 + 4)
= 25.66 cm