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If you good with 7th grade math pls help

If you good with 7th grade math pls help-example-1

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289 196 248 379 319 276 198 349

(in order) 196, 198, 248, 276, 289, 319, 349, 379 there are eight numbers.

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196, 198, 248, 276

since the median is between 198 and 248, we must add both numbers together and divide them by two:

(198 + 248) ÷ 2

= 446/2

= 223 (first quartile)

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289, 319, 349, 379

since the median is between 319 and 349, we must add both numbers together and divide them by two:

(319 + 349) ÷ 2

= 668/2

= 334 (third quartile)

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Interquartile range:

IQR: 334 - 223 = 111

I double-checked my answers btw

User Dennis Alund
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