menu
QAmmunity.org
Login
Register
My account
Edit my Profile
Private messages
My favorites
Register
Ask a Question
Questions
Tags
Categories
Ask a Question
as to how many M&M's do you think you'd get if you chose 2 today, 4tomorrow, 8 the next day, and continued that pattern for 2 weeks.
Pritam Kadam
asked
Jun 23, 2022
209,696
views
17
votes
17
votes
as to how many M&M's do you think you'd get if you chose 2 today, 4tomorrow, 8 the next day, and continued that pattern for 2 weeks.
Mathematics
high-school
Pritam Kadam
asked
Jun 23, 2022
by
Pritam Kadam
3.1k
points
answer
comment
share this
share
0 Comments
Your comment on this question:
Email me at this address if a comment is added after mine:
Email me if a comment is added after mine
Privacy: Your email address will only be used for sending these notifications.
Add comment
Cancel
Your answer
Email me at this address if my answer is selected or commented on:
Email me if my answer is selected or commented on
Privacy: Your email address will only be used for sending these notifications.
Add answer
Cancel
1
Answer
8
votes
8
votes
Answer:
32,766
Explanation:
you just keep multiplying by 2 14 times
Max Shron
answered
Jun 30, 2022
by
Max Shron
3.5k
points
ask related question
comment
share this
0 Comments
Your comment on this answer:
Email me at this address if a comment is added after mine:
Email me if a comment is added after mine
Privacy: Your email address will only be used for sending these notifications.
Add comment
Cancel
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.
1.6m
questions
2.0m
answers
Other Questions
Can anybody tell me what’s going on here?
Granola costs $1.76 per pound. Write and solve an equation to determine the number of pounds p of granola that can be purchased with $7.04. The equation is: The value of x is
PLZ needed now plz URGENT!
Yall help me out please
If y = sin 3x, find y" in terms of y.
Twitter
WhatsApp
Facebook
Reddit
LinkedIn
Email
Link Copied!
Copy
Search QAmmunity.org