Question

Saline is a 0,154 M NaCl solution.

If the mass of NaCl is used to prepare saline solution was 45,045 grams, find the volume of solution that was obtained.
(Na:23; Cl:35,5)

Answer 1

Answer: The volume of solution is 200 ml

Step-by-step explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

`Molarity=(n* 1000)/(V_s)`

where,

n = moles of solute

`V_s` = volume of solution in ml

moles of
`NaCl` =
`\frac{\text {given mass}}{\text {Molar mass}}=(45.045g)/(58.5g/mol)=0.77mol`

Now put all the given values in the formula of molality, we get

`0.154=(0.77* 1000)/(V_s)`

`V_s=(0.154* 1000)/(0.77)=200ml`

Therefore, the volume of solution is 200 ml