Answer:
Explanation:
41). Measure of an external angle of a triangle is equal to the sum of teh opposite two angles.
140° = (13x + 9)° + (5x + 5)°
140 = 18x + 14
18x = 140 - 14
18x = 126
x = 7
m∠R = (13x + 9)
= 13×7 + 9
= 100°
42). m∠DCA = m∠E + m∠D
126° = (6x + 2)° + (5x + 3)°
126 = 11x + 5
11x = 126 - 5
11x = 121
x = 11
m∠D = (5x + 3)
= 5(11) + 3
= 58°
43). m∠DPQ = m∠Q + m∠R
11x + 3 = 70° + (x + 13)°
11x + 3 = x + 83
11x - x = 83 - 3
10x = 80
x = 8
m∠R = (x + 13)
= 21°
44). m∠QST = m∠T + m∠U
13 + 13x = 100 + (3x + 3)
13 + 13x = 3x + 103
13x - 3x = 103 - 13
10x = 90
x = 9
m∠U = 3x + 3
= 3(9) + 3
= 27 + 3
= 30°