Question

HELP what's the distance for this question? ​

Answer 1

`Distance = 38.57ft`

Explanation:

Given

`Base = 60`

`\theta = 50`

Required

The distance between the top and John

The distance is calculated using:

`sin\alpha = (Distance)/(Base)`

Where

`\alpha = 90 - \theta` --- the angle between the diagonal line and the vertical line

`\alpha = 90 - 50`

`\alpha = 40`

So, we have:

`Sin(40) = (Distance)/(60)`

`Distance = 60 * sin(40)`

`Distance = 60 * 0.6428`

`Distance = 38.57ft`

`Distance = 986 * tan(38)`

`Distance = 986 * 0.7812`

`Distance = 770ft` --- approximated