22.8k views
3 votes
In ΔTUV, the measure of ∠V=90°, the measure of ∠U=85°, and VT = 20 feet. Find the length of TU to the nearest tenth of a foot.

User Handiansom
by
7.9k points

2 Answers

5 votes

Answer: 20.1

Explanation:

sinU=

hypotenuse

opposite

=

x

20

\sin 85=\frac{20}{x}

sin85=

x

20

x\sin 85=20

xsin85=20

Cross multiply.

\frac{x\sin 85}{\sin 85}=\frac{20}{\sin 85}

sin85

xsin85

=

sin85

20

Divide each side by sin 85.

x=\frac{20}{\sin 85}=20.0764\approx 20.1\text{ feet}

x=

sin85

20

=20.0764≈20.1 feet

Type into calculator and roundto the nearest tenth of a foot.

T

U

V

20

20.1

(opposite of ∠U)

(adj. to ∠U)

(hypotenuse)

85°

User Cosmosa
by
7.5k points
6 votes

Answer: 20.1

Step-by-step explanation: I if you are here from delta math this is the answer

User Igor Martins
by
8.5k points
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