Question

Um, ik i need help alot tonight lol

Answer 1

See below

Explanation:

`\frac{ {x}^(4) }{ {x}^( - 3) {y}^(0) } = \frac{ {x}^(4 + 3) }{ {y}^(0) } = \frac{ {x}^(7) }{1} = {x}^(7) \\ \\ 2 {x}^( - 3) = \frac{2}{ {x}^(3) } \\ \\ {( {x}^( - 3) )}^(8) = {x}^( - * 8) = {x}^( - 24) = \frac{1}{ {x}^(24) }`