Answer: This is a valid probability distribution.
The P(x) values add to 1; each P(x) is between 0 and 1 inclusive.
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Further Explanation:
A valid probability distribution is when,
- The P(x) values add to 1.
- Each P(x) value is between 0 and 1 inclusive; i.e.
![0 \le P(\text{x}) \le 1](https://img.qammunity.org/2023/formulas/mathematics/high-school/85gjciu8ymoz0plfd58m8d1gztzy9ommeb.png)
The given data table is:
![\begin{array} \cline{1-2}\text{x} & \text{P(x)}\\\cline{1-2}1 & 0.49\\\cline{1-2}2 & 0.05\\\cline{1-2}3 & 0.32\\\cline{1-2}4 & 0.07\\\cline{1-2}5 & 0.07\\\cline{1-2}\end{array}](https://img.qammunity.org/2023/formulas/mathematics/high-school/6tfs47cx4z4v4impcbt4aqoxko7p175g31.png)
It's fairly clear that rule 2 has been satisfied. Something like
is indeed a true statement. It's like saying 49% is between 0% and 100%. The other P(x) values are similar in nature.
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Let's see what the P(x) probability values add to:
0.49+0.05+0.32+0.07+0.07 = 1
We see that rule 1 has been met as well.
Since both rules have been satisfied, this means we have a valid probability distribution.