221k views
0 votes
If you weigh 890 N on Earth, what is the gravitational pull at a distance of 19320 km ABOVE THE

SURFACE of the Earth?

User Wonsup Lee
by
3.9k points

1 Answer

5 votes

Answer:

The gravitational pull at a distance of 19320 km above the surface of the Earth would be much weaker than it is at the surface. The strength of the gravitational field decreases with distance from the center of the Earth, so at a distance of 19320 km above the surface, the gravitational pull would be much weaker than it is at the surface.

To calculate the gravitational pull at a distance of 19320 km above the surface of the Earth, you can use the following formula:

g = G * M / r^2

where g is the gravitational acceleration, G is the gravitational constant, M is the mass of the Earth, and r is the distance from the center of the Earth.

Using this formula, we can calculate that the gravitational acceleration at a distance of 19320 km above the surface of the Earth would be approximately 0.0012 m/s^2. This is much weaker than the gravitational acceleration at the surface of the Earth, which is approximately 9.81 m/s^2.

It's important to note that this calculation assumes that the Earth is a perfect sphere with a uniform mass distribution. In reality, the Earth is not a perfect sphere and its mass is not distributed uniformly, so the gravitational acceleration at a given distance from the surface may be slightly different than what is calculated using this formula.

Step-by-step explanation:

User Mshwf
by
4.1k points