Answer: 20
x + y
12
x
5
y
3
Explanation:
You just write down what the question says, x is cashier and y is stockers.
The total number of both cashiers and stockers is 12 or more so x + y
12.
But, not over 20 so 20
x + y
12.
then "There must be at least 5 cashiers and 3 stockers." so x
5 and y
3
This is a system of inequalities:
20
x + y
12
x
5
y
3