Question

The amount of internal energy needed to raise the tempreture of .25kg of water by 0.2C is 209.3 J. how fast must a 0.25 kg baseball travel in order for its kinetic energy to equal this internal energy?

help me!

Answer 1

Step-by-step explanation:

To find the speed at which a 0.25 kg baseball must travel in order to have kinetic energy equal to 209.3 J, you will need to use the formula for kinetic energy, which is:

KE = 1/2 * m * v^2

Where KE is the kinetic energy, m is the mass of the object, and v is the speed of the object.

To solve for v, you will need to rearrange the equation to solve for v:

v = sqrt(2 * KE / m)

Plugging in the values given in the problem, we get:

v = sqrt(2 * 209.3 J / 0.25 kg)

Solving this equation gives us a speed of approximately 29.3 meters per second. This is the speed at which the 0.25 kg baseball must travel in order to have kinetic energy equal to 209.3 J.

I hope this helps!