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5 V battery with metal wires attached to each end.

The figure shows two wires connected to a battery’s positive and negative terminals. These wires stop short of completing a circuit. Four points are marked on the wires. Point 1 is at the end of the wire connected to the positive terminal. Point 2 is at the negative terminal. Point 3 is at the positive terminal. Point 4 is at the end of the wire connected to the negative terminal.
What are the potential differences ΔV12=V2−V1, ΔV23=V3−V2, ΔV34=V4−V3, and ΔV41=V1−V4?
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User Selecsosi
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Final answer:

The potential differences can be calculated using the formula ΔV = V2 - V1, where V2 is the voltage at the second point and V1 is the voltage at the first point. Since we are dealing with a battery, the potential difference between the positive and negative terminals is equal to the voltage of the battery.

Step-by-step explanation:

The potential differences can be calculated using the formula ΔV = V2 - V1, where V2 is the voltage at the second point and V1 is the voltage at the first point.

So, ΔV12 = V2 - V1, ΔV23 = V3 - V2, ΔV34 = V4 - V3, and ΔV41 = V1 - V4.

Since we are dealing with a battery, the potential difference between the positive and negative terminals is equal to the voltage of the battery. So, we can substitute V3 with the voltage of the battery in the calculations.

User Convex
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