Question

A) In a single throw of 2 dice, find the probability of getting product at most 6.

Answer 1

Answer: There are a total of 6 * 6 = 36 outcomes when two dice are thrown.

The outcomes that result in a product at most 6 are (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (3, 1), (3, 2), (3, 3), (4, 1), and (5, 1).

There are a total of 15 outcomes that result in a product at most 6.

Therefore, the probability of getting a product at most 6 in a single throw of 2 dice is 15/36, which is approximately 0.417.

Explanation:

Answer 2

p(product of at most 6) = 13/36

Explanation:

When throwing 2 dice, there are 36 possible outcomes.

Here are the 36 possible outcomes and their products.

1, 1: 1 <---- at most 6

1, 2: 2 <---- at most 6

1, 3: 3 <---- at most 6

1, 4: 4 <---- at most 6

1, 5: 5 <---- at most 6

1, 6: 6 <---- at most 6

2, 1: 2 <---- at most 6

2, 2: 4 <---- at most 6

2, 3: 6 <---- at most 6

2, 4: 8

2, 5: 10

2, 6: 12

3, 1: 3 <---- at most 6

3, 2: 6 <---- at most 6

3, 3: 9

3, 4: 12

3, 5: 15

3, 6: 18

4, 1: 4 <---- at most 6

4, 2: 8

4, 3: 12

4, 4: 16

4, 5: 20

4, 6: 24

5, 1: 5 <---- at most 6

5, 2: 10

5, 3: 15

5, 4: 20

5, 5: 25

5, 6: 30

6, 1: 6 <---- at most 6

6, 2: 12

6, 3: 18

6, 4: 24

6, 5: 30

6, 6: 36

There are 36 possible outcomes.

There are 13 outcomes of at most 6.

p(product of at most 6) = 13/36