y-6=-1/2(x+1)
1. the point-slope form is y-y1=m(x-x1)
x1 and y1 are the coordinates of the point (-1,6) because the line we are looking for its equation passes through it. "m" is the slope.
2. plug in the point (-1,6) in the form from step 1
y-6=m(x+1)
3. to find the slope of this line, the question tells us that this line is parallel to another line that passes through two given points. Any parallel lines, their slopes are the same. That means we have to find the slope of the 2nd line and use it for the 1st line.
The slope formula is m=(y2-y1)/(x2-x1)
plug in the two points m=(4-2)/(2-6), which is equal to -1/2
4. plug in "m" value in the equation from step 2.
Done