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a line with a slope of 1/10 passes through the point (20,2). what is its equation in slope-intercept form?

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5 votes

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Answer:
y= (1)/(10)x

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Given:
\textsf{Slope = 1/10 and goes through (20, 2)}

Find:
\textsf{Slope in slope-intercept form}

Solution: First we need to plug into the point slope formula which is
(y - y_1) = m(x - x_1). Let us plug in the values first and then solve for the slope-intercept form.

Plug in the values


  • (y - y_1) = m(x - x_1)

  • (y - 2) = (1)/(10)(x - 20)

Simplify


  • y - 2 = ((1)/(10) * x)+((1)/(10)*-20)

  • y - 2 = (1)/(10)x-2

  • y - 2 + 2 = (1)/(10)x-2 + 2

  • y= (1)/(10)x

Answer: Therefore, the final answer in slope-intercept form for the line with a slope of 1/10 that passes through the point (20, 2) is
y= (1)/(10)x

User Dsavickas
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