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Find the perimeter of quadrilateral ABCD. Round your answer to the nearest hundredth. A(3, 5) B(1, 3) C(3, -1) D(5, 3)

User Gorokizu
by
3.0k points

1 Answer

23 votes
23 votes

Answer:

Perimeter = 4(√2 + √5) units

Explanation:

Given:

Quadrant of 4 points;

A(3, 5) B(1, 3) C(3, -1) D(5, 3)

Find:

Perimeter

Computation:

Distance = √(x1 - x2)² + (y1 - y2)²

Distance between AB = √(3 - 1)² + (5 - 3)²

Distance between AB = √4 + 4

Distance between AB = 2√2 units

Distance between BC = √(1 - 3)² + (3 + 1)²

Distance between BC = √4 + 16

Distance between BC = 2√5 units

Distance between CD = √(3 - 5)² + (-1 - 3)²

Distance between CD = √4 + 16

Distance between CD = 2√5 units

Distance between DA = √(5 - 3)² + (3 - 5)²

Distance between DA = √4 + 4

Distance between DA = 2√2 units

Perimeter = sum of all sides

Perimeter = 2√2 + 2√5 + 2√2 + 2√5

Perimeter = 4√2 + 4√5

Perimeter = 4(√2 + √5) units

User Stav Shamir
by
3.2k points