Answer:
108 degrees
Explanation:
lets imagine that pqr are the angles of the triangle
<rpq=53°(opposite<)
for <prq 180°-125°(< on a straight line)=55°
<pqr= a+b+c
= 55°+53°+c= 180°(< in a ∆)
= 108°+c =180°
collect like terms
c= 108°-108°
c= 72°
Therefore<pqr= 72°
for the unknown angle which is x
55+53=108( the two sides are facing the exterior <)