Question

You mix a solution of an unknown ionic compound with 10 mL of a 0.5 M solution of silver nitrate. The resulting mixture forms a grayish-white precipitate immediately upon mixing. You dry and weigh the solid, and find that it has a mass of 716.6 mg. Which of the following is the unknown solution? Write a balanced chemical equation for the resulting reaction. a. 5 mL of 0.5 M sodium acetate b. 10 mL of 0.5 M lithium bromide c. 15 mL of 0.8 M ammonium chloride

Answer 1

the answer is is ...is..... i don't know, I'm sorry, but i need the points :(

Answer 2

c. 15 mL of 0.8 M ammonium chloride

Step-by-step explanation:

ammonium chloride contains ammonium ions (NH4+) and chloride ions (Cl-). If the unknown solution were ammonium chloride, the reaction with silver nitrate would produce a compound containing silver ions and chloride ions, which is silver chloride (AgCl). Silver chloride is a white solid that readily forms a precipitate when mixed with water, which is consistent with the observed results.

The balanced chemical equation for the reaction between silver nitrate and ammonium chloride is:

AgNO3 + NH4Cl -> AgCl + NH4NO3

Therefore, the unknown solution is likely 15 mL of 0.8 M ammonium chloride.