204k views
2 votes
Graph the line with slope 1/5 and y intercept 7

User Diavolic
by
8.7k points

1 Answer

1 vote

Answer:

y = (1/5)x + 7

Explanation:

The slope of a line is a measure of its steepness, or how much it rises or falls for a given horizontal change. A slope of 1/5 means that for every 5 units of horizontal change (measured along the x-axis), the line rises or falls by 1 unit (measured along the y-axis).

The y-intercept of a line is the point at which the line crosses the y-axis. In the case of the line with slope 1/5 and y intercept 7, the y-intercept is the point (0, 7), which means that the line crosses the y-axis at y = 7.

To graph the line with slope 1/5 and y intercept 7, we can use the slope-intercept form of the equation of a line, which is:

y = mx + b

Where m is the slope of the line and b is the y-intercept.

Substituting the values for the slope and y-intercept, we get:

y = (1/5)x + 7

This is the equation of the line. To graph the line, we can plot points that satisfy this equation and then draw a straight line through those points.

For example, if we substitute x = 0 into the equation, we get y = 7, which is the y-intercept. So, the point (0, 7) lies on the line.

If we substitute x = 1 into the equation, we get y = (1/5)(1) + 7 = (1/5) + 7 = 8/5 + 7 = 53/5. So, the point (1, 53/5) lies on the line.

We can repeat this process for other values of x to find more points on the line, and then connect these points with a straight line to graph the line.

User Kostadin
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.