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Graph the line with slope 1/5 and y intercept 7

User Diavolic
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1 Answer

1 vote

Answer:

y = (1/5)x + 7

Explanation:

The slope of a line is a measure of its steepness, or how much it rises or falls for a given horizontal change. A slope of 1/5 means that for every 5 units of horizontal change (measured along the x-axis), the line rises or falls by 1 unit (measured along the y-axis).

The y-intercept of a line is the point at which the line crosses the y-axis. In the case of the line with slope 1/5 and y intercept 7, the y-intercept is the point (0, 7), which means that the line crosses the y-axis at y = 7.

To graph the line with slope 1/5 and y intercept 7, we can use the slope-intercept form of the equation of a line, which is:

y = mx + b

Where m is the slope of the line and b is the y-intercept.

Substituting the values for the slope and y-intercept, we get:

y = (1/5)x + 7

This is the equation of the line. To graph the line, we can plot points that satisfy this equation and then draw a straight line through those points.

For example, if we substitute x = 0 into the equation, we get y = 7, which is the y-intercept. So, the point (0, 7) lies on the line.

If we substitute x = 1 into the equation, we get y = (1/5)(1) + 7 = (1/5) + 7 = 8/5 + 7 = 53/5. So, the point (1, 53/5) lies on the line.

We can repeat this process for other values of x to find more points on the line, and then connect these points with a straight line to graph the line.

User Kostadin
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