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in triangle ABC, AB = 6 cm, BC = 13cm and angle ACB = 23 degrees. Calculate angle BÁC, which is obtuse.
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in triangle ABC, AB = 6 cm, BC = 13cm and angle ACB = 23 degrees. Calculate angle BÁC, which is obtuse.

in triangle ABC, AB = 6 cm, BC = 13cm and angle ACB = 23 degrees. Calculate angle-example-1
User Stefan Neubert
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1 Answer

2 votes

Answer:


\angle BAC=180^(\circ)-(13\sin 23^(\circ))/(6)

Explanation:


(\sin(\angle BAC))/(13)=(\sin 23^(\circ))/(6) \\ \\ \sin \angle BAC=(13\sin 23^(\circ))/(6) \\ \\ \angle BAC=180^(\circ)-(13\sin 23^(\circ))/(6)

User Shaul Zuarets
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