148k views
0 votes
An electron in a long, organic molecule used in a dye laser behaves approximately like a quantum particle in a box with width 4.18 nm. Find the emitted photon when the electron makes a transition from the first excited state to the ground state and from the second excited state to the first excited state.

User Ccyan
by
8.0k points

1 Answer

2 votes

Final answer:

To find the wavelength of emitted photons in a dye laser, use the equation E = hc / λ.

Step-by-step explanation:

When an electron in the organic molecule makes a transition from the first excited state to the ground state, it emits a photon. The energy of this emitted photon can be found using the equation E = hc / λ, where E is the energy, h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon.

We can rearrange this equation to solve for λ: λ = hc / E. Plugging in the energy difference between the first excited state and the ground state, we can calculate the wavelength of the emitted photon.

Similarly, when the electron makes a transition from the second excited state to the first excited state, it again emits a photon. We can use the same equation to calculate the wavelength of this photon.

User Ben Arent
by
8.3k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.