Question

An electron in a long, organic molecule used in a dye laser behaves approximately like a quantum particle in a box with width 4.18 nm. Find the emitted photon when the electron makes a transition from the first excited state to the ground state and from the second excited state to the first excited state.

Answer 1

To find the wavelength of emitted photons in a dye laser, use the equation E = hc / λ.

Step-by-step explanation:

When an electron in the organic molecule makes a transition from the first excited state to the ground state, it emits a photon. The energy of this emitted photon can be found using the equation E = hc / λ, where E is the energy, h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon.

We can rearrange this equation to solve for λ: λ = hc / E. Plugging in the energy difference between the first excited state and the ground state, we can calculate the wavelength of the emitted photon.

Similarly, when the electron makes a transition from the second excited state to the first excited state, it again emits a photon. We can use the same equation to calculate the wavelength of this photon.