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What is the equation in point-slope form of the line that passes through the points (-3, -1) and (2, 9)?

y-1 = 2(x+3)
y-9=2(x-2)
y+9=2(x-2)
y-1= 2(x-3)

User Von Spotz
by
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1 Answer

1 vote

Answer:


\textsf{B)} \quad y-9=2(x-2)

Explanation:


\boxed{\begin{minipage}{9cm}\underline{Slope Formula}\\\\Slope $(m)=(y_2-y_1)/(x_2-x_1)$\\\\where $(x_1,y_1)$ and $(x_2,y_2)$ are two points on the line.\\\end{minipage}}

Given points:

  • (-3, -1)
  • (2, 9)

Substitute the given points into the slope formula to find the slope of the line:


\implies m=(9-(-1))/(2-(-3))=(10)/(5)=2


\boxed{\begin{minipage}{5.8 cm}\underline{Point-slope form of a linear equation}\\\\$y-y_1=m(x-x_1)$\\\\where:\\ \phantom{ww}$\bullet$ $m$ is the slope. \\ \phantom{ww}$\bullet$ $(x_1,y_1)$ is a point on the line.\\\end{minipage}}

Substitute the found slope and point (-3, -1) into the point-slope formula:


\implies y-(-1)=2(x-(-3))


\implies y+1=2(x+3)

Substitute the found slope and point (2, 9) into the point-slope formula:


\implies y-9=2(x-2)

Therefore, the correct answer option is:


\textsf{B)} \quad y-9=2(x-2)

User Stenix
by
7.7k points

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