75.6k views
5 votes
What is the distance between the points (-2,3) and (5, -1)?

User Gfjr
by
7.9k points

2 Answers

1 vote

Answer:

√65

Explanation:

Compute the Euclidean distance between the following points:

p_1 = (-2, 3) and p_2 = (5, -1)

The Euclidean distance between points (x_1, y_1) and (x_2, y_2) is:

sqrt((x_1 - x_2)^2 + (y_1 - y_2)^2)

Substitute (x_1, y_1) = (-2, 3) and (x_2, y_2) = (5, -1):

= sqrt((-2 - 5)^2 + (--1 + 3)^2)

(-1)^2 = 1:

= sqrt((-2 - 5)^2 + (1 + 3)^2)

-2 - 5 = -(2 + 5):

= sqrt((-(2 + 5))^2 + (3 + 1)^2)

2 + 5 = 7:

= sqrt((-7)^2 + (3 + 1)^2)

Multiply each exponent in -7 by 2:

= sqrt((-1)^2×7^2 + (3 + 1)^2)

7^2 = 49:

= sqrt((-1)^2×49 + (3 + 1)^2)

(-1)^2 = 1:

= sqrt(49 + (3 + 1)^2)

3 + 1 = 4:

= sqrt(49 + 4^2)

4^2 = 16:

= sqrt(49 + 16)

| 1 |

| 4 | 9

+ | 1 | 6

| 6 | 5:

Answer: √65

User Ariel Malka
by
7.5k points
3 votes
The distance between the points (-2,3) and (5.-1) is 10
User Shonta
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories