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What is the midpoint of (1,5) and (7,11)

User Graviton
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1 Answer

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Answer:

(4,8)

Explanation:

First, Let us see the midpoint formula:

m(x,x /2, y,y/2) (That probably looks really confusing online)

Let us label our cords

A: (1x,5y)

B: (7x,11y)

Now, Add the x's together

7x + 1 = 8

8÷2 = 4

Now, Add the y together

11 + 5 = 16

16÷2 = 8

(4,8)

User Teovald
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