Question

The path of a projectile launched from a 26-ft-tall tower is modeled by the equation y = −16t2 + 64t + 26. What is the maximum height, in feet, reached by the projectile?

Answer 1

The maximum height of the projectile is 90 ft

Explanation:

Here, we want to get the maximum height reached by the projectile

The answer here will be the y-coordinate value of the vertex form of the given equation

so firstly, we have to write the equation in the vertex form

We have this as;

y = -16t^2 + 64t + 26

That will be;

y = a(x-h)^2 + k

y = -16(x-2)^2 + 90

where the vertex of the equation is;

(-h,k)

K

in this case is 90 and thus, that is the maximum height of the projectile