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Write the equation of the line that is perpendicular to the x-axis and passes through the point (6,-2).

User Cky
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1 Answer

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The slope of a line that is perpendicular to the x-axis is undefined, so we cannot use the standard form of the equation of a line, y = mx + b, where m is the slope of the line. Instead, we can use the point-slope form of the equation of a line, which is given by y - y1 = m(x - x1). In this case, m is undefined, so we can simplify the equation to y = x1 - y1, where x1 and y1 are the coordinates of the point that the line passes through. In our case, this gives us the following equation:

y = 6 - (-2)

= 8

Therefore, the equation of the line that is perpendicular to the x-axis and passes through the point (6,-2) is y = 8.

User Midge
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