Answer:
1.57 mol NaN₃
Step-by-step explanation:
- 2 NaN₃ (s) → 2 Na (s) + 3 N₂ (g)
First we use PV=nRT to calculate the number of N₂ moles that need to be produced:
- R = 0.082 atm·L·mol⁻¹·K⁻¹
- T = 23.7 °C ⇒ 23.7 + 273.16 = 296.86 K
Inputing the data:
- 1.07 atm * 53.4 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 296.86
And solving for n:
Finally we convert N₂ moles into NaN₃ moles, using the stoichiometric coefficients of the balanced reaction:
- 2.35 mol N₂ *
= 1.57 mol NaN₃