Question

A ball is thrown into the air. Its height in

feet after t seconds is given by the
function h(t) = −5t² + 20t. How high will
the ball be after 3 seconds?

Answer 1

15 ft

Explanation:

• h(t) = −5t² + 20t (Given)

• We need to find: height of the ball after 3 seconds.

• So, plug t = 3 in the above equation, we find:

• h(3) = −5(3)² + 20(3)

• ->h(3) = −5(3)² + 20(3)

• ->h(3) = −5(9) + 60

• ->h(3) = −45 + 60

• ->h(3) = 15 feet