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The rational roots theorem - state the possible rational zeros for each function (please show work)

f(x)=3x^2+2x-1

User Muhmuhten
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1 Answer

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Answer: x=-1 x=1/3

Explanation:

f(x)=3x²+2x-1


3x^2+2x-1=0\\\\3x^2+(3x-x)-1=0\\\\(3x^2+3x)-x-1=0\\\\3x(x+1)-(x+1)=0\\\\(x+1)(3x-1)=0\\\\x+1=0\\\\x=-1\\\\3x-1=0\\\\3x=1

Divide both parts of the equation by 3:


\displaystyle\\x=(1)/(3)

User Twin Caret
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