Answer:
Explanation:
You want the values of y and z in the figure showing a triangle with exterior angle 135° opposite remote interior angles (5y+5)° and (4z+9)°, where angle (4z+9)° is adjacent to exterior angle (9y-2)°.
Exterior angle
The exterior angle of a triangle is equal to the sum of the remote interior angles. This can be used to find both y and z.
The lower left interior angle is 180° -135° = 45°, so the right-side exterior angle is ...
(9y -2)° = (5y +5)° +45°
4y = 52 . . . . . . . . . . . . . divide by °, add 2-5y
y = 13 . . . . . . . . . . divide by 4
The lower left exterior angle is ...
135° = (5y +5)° +(4z +9)°
135 = 5(13) +5 +4z +9 . . . . . . . . . divide by °, substitute value of y
56 = 4z . . . . . . . . . . . . . . . . subtract 79
14 = z . . . . . . . . . . . . divide by 4
The values of y and z are 13 and 14, respectively.