Question

(please explain and show work/drawing. thank you so much!) In a certain Algebra 2 class of 22 students, 5 of them

play basketball and 11 of them play baseball. There are 3
students who play both sports. What is the probability that
a student chosen randomly from the class plays basketball
or baseball?

Answer 1

59%

Explanation:

First, let's find the number of students who play basketball but not baseball: 5 students - 3 students = <<5-3=2>>2 students

Next, let's find the number of students who play baseball but not basketball: 11 students - 3 students = <<11-3=8>>8 students

Now, let's add up the number of students who play basketball but not baseball, the number of students who play baseball but not basketball, and the number of students who play both sports to find the total number of students who play basketball or baseball: 2 students + 8 students + 3 students = <<2+8+3=13>>13 students

Finally, we can divide the total number of students who play basketball or baseball by the total number of students in the class to find the probability that a student chosen at random plays basketball or baseball: 13 students / 22 students = 0.59

Therefore, the probability that a student chosen at random from the class plays basketball or baseball is 0.59.

Answer 2

13/22

Explanation:

The class has 22 students.

5 play basketball.

11 play baseball.

3 play both.

Break down the 5 who play basketball into:

2 play only basketball

3 play both basketball and baseball

Break down the 11 who play baseball into:

8 play only baseball

3 play both basketball and baseball (These 3 are the same 3 above)

Now we have:

2 play only basketball

8 play only baseball

3 play both

This is a total of 13.

The class has 22, so 9 don't play any sport.

That means out of 22 students, 13 play either sport, and 9 play nothing.

p(basketball or baseball) = 13/22