Question

The one-to-one function is defined below.
Please help with this answer i’m struggling.

Answer 1

<=> (8+9y)x=-y+9

<=> 8x+9yx+y=9

<=> y(9x+1)=9-8x

<=> y=(9-8x)/(9x+1)

domain: 9x+1
`\geq` 0 <=> x
`\geq` -1/9 => R / {-1/9}

range: R/{-8/9} (horizontal asymptot)