Question

Please urgent

7. The average force applied by the engine of a 1200 kg car is 900 N. If the car is
initially traveling at 15 m/s, how fast will it be traveling 300 m farther down the road?

Answer 1

final speed will be 25.98 m/s Explanation Force applied by the engine on the car is We have to find final speed of the car after travelling 300 m , so displacement of car is given as so wor done by the engines on the car

Answer 2

`F=ma \\ 900 = 1200a \\ a = (3)/(4) m. {s}^( - 2) \\ {v}^(2) = {u}^(2) +2 as \\ {v}^(2) = {(15)}^(2) + 2( (3)/(4) )(300) \\ = 675 \\ v = √(675) \: m. {s}^( - 1)`