Answer:
The acceleration of the plane is given by the equation a = F/m, where F is the thrust force and m is the mass of the plane. Therefore, the acceleration of the plane is given by a = F/22 kg.
The normal reaction on the nose wheel at A is given by the equation R_A = F + mg, where F is the thrust force and m is the mass of the plane. The normal reaction on the two wing wheels at B is given by the equation R_B = mg, where m is the mass of the plane. Therefore, the normal reaction on the nose wheel at A is given by R_A = F + 22 kg and the normal reaction on the two wing wheels at B is given by R_B = 22 kg.
Step-by-step explanation: