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What is the solution to the compound inequality in interval notation?

4(x +1) > -4 or 2x - 4 < -10

User Gil Perez
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1 Answer

5 votes

Answer:
(-\infty, -3) \ \cup (-2, \infty)

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Step-by-step explanation:

Let's solve the first inequality.

4(x+1) > -4

4x+4 > -4

4x > -4-4

4x > -8

x > -8/4

x > -2

The inequality sign doesn't flip since we didn't divide both sides by a negative value.

Now let's solve the other inequality.

2x-4 < -10

2x < -10+4

2x < -6

x < -6/2

x < -3

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To summarize:

  • solving 4(x+1) > -4 leads to x > -2
  • solving 2x-4 < -10 leads to x < -3

Draw out a number line. Place open holes at -3 and -2.

Shade to the right of -2 and to the left of -3 to indicate x > -2 and x < -3 respectively.

See the diagram below.

The interval in red is x < -3. This is the same as
-\infty < \text{x} < -3 and that becomes the interval notation
(-\infty, -3)

The interval in blue is x > -2. It is the same as
-2 < \text{x} < \infty which becomes the interval notation
(-2, \infty)

Glue those interval notations together to end up with the final answer of
(-\infty, -3) \ \cup (-2, \infty)

The "U" is the union symbol.

What is the solution to the compound inequality in interval notation? 4(x +1) &gt-example-1
User Mihnea Simian
by
8.5k points

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