109k views
4 votes
What is the solution to the compound inequality in interval notation?

4(x +1) > -4 or 2x - 4 < -10

User Gil Perez
by
8.4k points

1 Answer

5 votes

Answer:
(-\infty, -3) \ \cup (-2, \infty)

====================================================

Step-by-step explanation:

Let's solve the first inequality.

4(x+1) > -4

4x+4 > -4

4x > -4-4

4x > -8

x > -8/4

x > -2

The inequality sign doesn't flip since we didn't divide both sides by a negative value.

Now let's solve the other inequality.

2x-4 < -10

2x < -10+4

2x < -6

x < -6/2

x < -3

-----------------------------------

To summarize:

  • solving 4(x+1) > -4 leads to x > -2
  • solving 2x-4 < -10 leads to x < -3

Draw out a number line. Place open holes at -3 and -2.

Shade to the right of -2 and to the left of -3 to indicate x > -2 and x < -3 respectively.

See the diagram below.

The interval in red is x < -3. This is the same as
-\infty < \text{x} < -3 and that becomes the interval notation
(-\infty, -3)

The interval in blue is x > -2. It is the same as
-2 < \text{x} < \infty which becomes the interval notation
(-2, \infty)

Glue those interval notations together to end up with the final answer of
(-\infty, -3) \ \cup (-2, \infty)

The "U" is the union symbol.

What is the solution to the compound inequality in interval notation? 4(x +1) &gt-example-1
User Mihnea Simian
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories