Question

A teacher is flying a drone as shown in the diagram below. The drone is maintaining a height of approximately 150 feet above his eye level. What is the approximate angle of elevation from his eye level to the drone when the drone is approximately 200 feet away from him?​

Answer 1

Angle of elevation = 48.60° (Approx.)

Explanation:

Given:

Vertical Height = 150 feet

Horizontal angular length of drone = 200 feet

Find:

Angle of elevation

Computation:

Using trigonometry function

⇒ Sinθ = Perpendicular / Hypotenuse

⇒ Sinθ = Vertical Height / Horizontal angular length of drone

⇒ Sinθ = 150 / 200

⇒ Sinθ = 0.75

⇒ Sin⁻¹(0.75) = θ

Angle of elevation = 48.60° (Approx.)