1 Answer

Morten Hjort · Answer 1 · 2023-07-10T08:22:00+0000

Answer: 2

Explanation:

The object hits the ground when
h=0 .

$-16t^2 +128t+144=0\\\\t^2 -8t-12=0\\\\(t-2)(t-6)=0\\\\t=2, 6$

However, if we consider the graph, since the height must initially be positive, we take the case where
t=2 .

Please log in or register to add a comment.