162k views
1 vote
Reciprocal Linear Trig Equations

Reciprocal Linear Trig Equations-example-1
User Kaykay
by
8.4k points

1 Answer

7 votes

Answer:

θ

=

41.3

,

138.7

,

221.3

,

318.7

Step-by-step explanation:

3

sin

2

θ

10

(

1

2

sin

2

θ

)

=

0

23

sin

2

θ

10

=

0

sin

2

θ

=

10

23

sin

θ

=

±

10

23

θ

=

arcsin

(

10

23

)

=

41.3

θ

=

arcsin

(

10

23

)

=

41.3

+

360

=

318.7

We missed the solutions in quadrants 2 and 3 as arcsin is restricted to quadrants 1 and 4:

So:

41.3

+

180

=

221.3

318.7

180

=

138.7

Step-by-step explanation:

There you go

User Ioncannon
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories