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Reciprocal Linear Trig Equations

Reciprocal Linear Trig Equations-example-1
User Kaykay
by
4.4k points

1 Answer

7 votes

Answer:

θ

=

41.3

,

138.7

,

221.3

,

318.7

Step-by-step explanation:

3

sin

2

θ

10

(

1

2

sin

2

θ

)

=

0

23

sin

2

θ

10

=

0

sin

2

θ

=

10

23

sin

θ

=

±

10

23

θ

=

arcsin

(

10

23

)

=

41.3

θ

=

arcsin

(

10

23

)

=

41.3

+

360

=

318.7

We missed the solutions in quadrants 2 and 3 as arcsin is restricted to quadrants 1 and 4:

So:

41.3

+

180

=

221.3

318.7

180

=

138.7

Step-by-step explanation:

There you go

User Ioncannon
by
4.1k points