Question

Help!! Its A Math Problem ! I am not sure how to solve it!! or show my work

Answer 1

Explanation:

#1.

2x² + 24x + 10 = 0

2(x² + 12x + 5) = 0

2[ x² + 2(6)x + 6² - 6² + 5 ] = 0

2[(x + 6)² - 31] = 0

2( x + 6 - √31 )( x + 6 + √31 ) = 0

`x_(1)` = - 6 + √31

`x_(2)` = - 6 - √31

#2.

f(x) = 3x² - 36x - 12

f(x) = 3( x² - 12x - 4 )

f(x) = 3 [ x² - 2(6)x + 6² - 6² - 4 ]

f(x) = 3 [( x - 6 )² - 40 ]

f(x) = 3( x - 6 )² - 120