Question

Calculate the distance between the points Q=(1,0) and B= (-2.-3) in the coordinate plane.

Round your answer to the nearest hundredth.

Answer 1

Answer: QB≈4.24

Explanation:

Q(1,0) B(-2,-3) QB=?

`\boxed{L=√((x_2-x_1)+(y_2-y_1)^2) }\\\\x_1=1\ \ \ \ x_2=-2\ \ \ \ y_1=0\ \ \ \ y_2=-3`

Hence,

`QB=√((-2-1)^2+(-3-0)^2) \\\\QB=√((-3)^2+(-3)^2) \\\\QB=√(9+9) \\\\QB=√(18) \\\\QB=√(9(2)) \\\\QB=√(3^2(2)) \\\\QB=3√(2) \\\\QB\approx4.24`