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4 votes
Calculate the distance between the points Q=(1,0) and B= (-2.-3) in the coordinate plane.

Round your answer to the nearest hundredth.

User Enguerran
by
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1 Answer

6 votes

Answer: QB≈4.24

Explanation:

Q(1,0) B(-2,-3) QB=?


\boxed{L=√((x_2-x_1)+(y_2-y_1)^2) }\\\\x_1=1\ \ \ \ x_2=-2\ \ \ \ y_1=0\ \ \ \ y_2=-3

Hence,


QB=√((-2-1)^2+(-3-0)^2) \\\\QB=√((-3)^2+(-3)^2) \\\\QB=√(9+9) \\\\QB=√(18) \\\\QB=√(9(2)) \\\\QB=√(3^2(2)) \\\\QB=3√(2) \\\\QB\approx4.24

User Ian Bytchek
by
7.9k points

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