Answer:
4,886.83feet
Explanation:
The question will result in a right triangle with
Opposite = distance of the balloon above the ground = 950feet
Angle of elevation = 11 degrees
Required
Horizontal distance h (adjacent)
Using SOH CAH TOA identity
Tan theta =opp/adj
Tan 11 = 950/h
h = 950/tan 11
h = 950/0.1944
h = 4,886.83feet
Hence the horizontal distance from the balloon to the ground crew is 4,886.83feet